How do I solve 'at least one' probability problems on the SAT?
For 'at least one' problems, use the complement strategy: calculate the probability of the opposite (zero successes) and subtract from 1. For example, with a fair coin tossed 5 times, the probability of at least one head is 1 minus the probability of all tails, which is 1 minus (1/2)^5, equaling 31/32.



